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习题练习:SL/HL Topic C1.1 Enzymes and metabolism

 作者: admin   总分: 16分  得分: _____________

答题人: 游客未登录  开始时间: 25年01月31日 10:44  切换到: 整卷模式

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1#
 
单选题 ( 1.0 分) (组内1/4) 切至整卷模式 搜藏此题  
第 1 题组 (共 4 题 4 分)
  1. How is reliability estgtdjt(q co k-rqs:zq 1926 7zf0lt r:tablished in an enzyme experiment?

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2#
 
单选题 ( 1.0 分) (组内2/4) 切至整卷模式 搜藏此题  
  2. What can cause an enzyme to be denatured? 1 fsy6fnr-au,4 5prlk

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3#
 
单选题 ( 1.0 分) (组内3/4) 切至整卷模式 搜藏此题  
  3. Which of the following correctly describe aspects/q;wk;y+:h 6euftzp d of a metabolic pathway?
I. It is regulated by one enzyme.
II. It is a series of reactions to produce an end product.
III. It is a system producing energy.
IV. It can be anabolic or catabolic in nature.

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4#
 
单选题 ( 1.0 分) (组内4/4) 切至整卷模式 搜藏此题  
  4. The binding of the substrate to the active site of an enzyme cak v)/95n 5tq9 jvow;jtsl8 fevuses which of t)f woj 5q 98t9sv; k5/vntjevlhe following changes?
I. A change in the shape of the active site.
II. A change in the shape of the substrate.
III. A lowering of the activation energy of the reaction.
IV. The denaturation of the enzyme.

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5#
 
问答题 ( 1.0 分) (组内1/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第1/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
I. Explain why glucose is formed in the reato:od 3gdz7 vq3 )cry9ction mixture.
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6#
 
问答题 ( 1.0 分) (组内2/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第2/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
II. List two variables that should be cocrpfn u-r: j;+ntrolled in this experiment, other than thf; pj-+runc r:ose given.
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7#
 
问答题 ( 1.0 分) (组内3/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第3/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
III. Does the data collected indicate that the rate of the reaction z4zsq o.(t+xj is constant in the first 3 minutes?xz jst +4zq(o.
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8#
 
问答题 ( 1.0 分) (组内4/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第4/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
IV. Calculate the rate of ,e96cg. fdreob4e/zg) 3;p( dbn l ztt;st mv;reaction in the first 5 minutes
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9#
 
问答题 ( 1.0 分) (组内5/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第5/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
V. Describe the changes in the rate of reaction fromagr e;*)w1g ih*9 irsd the $4^{th}$ to the $8^{th}$ minute.
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10#
 
问答题 ( 1.0 分) (组内6/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第6/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
VI. Why was it not necessary tt2 t:hm uk()zeo collect data after the $8^{th}$ minute?
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11#
 
问答题 ( 1.0 分) (组内7/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第7/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
VII. Predict, with a reason, the fructose concgj:;oz wiarej+ 1d(1 yentration in the reaction mixture at thegj;1ya+o z:re1w (d ij $6^{th}$ minute.
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12#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 3 题组 (共 1 题 1 分)
6. Enzymes are specific to a particular reaction. Explain why en 4wc+ji 2jfbb)zyme specificity is important in the controlc wb2 j)jb4fi+ of metabolic pathways.
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13#
 
问答题 ( 1.0 分) (组内1/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第1/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
I. Penicillin does not affect(sfgv -1lcli5 kga(5x human enzymes.
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14#
 
问答题 ( 1.0 分) (组内2/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第2/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
II. Penicillin is a permanent competitive inhibitor of transpeptidase.dbg9;4x +nf ,u-:8ra mzbo oqg
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15#
 
问答题 ( 1.0 分) (组内3/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第3/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
III. Suggest how penicillin resistancn) sij-ufg(ude*zat q0q+/nx1 l+et .mt5 o 0re has developed in some bacteria.
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16#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 5 题组 (共 1 题 1 分)
8. ATP is an allosteric inhibitor of phosphofructokinase and pyruvate kin c 6qagv,j:x(jk,wbj- ase, two enzymes involved in glycolysis. Discuss the importance of feedback inhibition of metabolic pathways in biological systems using this as an examplc-j:j,a b6,w qg(vkjx e.
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