无忧得胜-网上国际课程 (5edu.win)

 找回密码
 立即注册

 

      

上传图片附件

未使用图片

小贴士: 允许的图片文件格式为: gif, jpg, jpeg, png, webp,上传完成后会在上方生成预览,用鼠标连续双击缩略图,或拖动缩略图,该图片就被绑定至本题,显示在题目下方

本次作答已使用

小贴士: 此栏目显示的是当前作答使用的所有图片,绑定到某一题目的图片同时会显示在该题目下方; 删除使用的图片会将其转移到<未使用图片>类别


习题练习:SL/HL Topic D3.2 Inheritance

 作者: admin 发布日期: 2025-02-01 15:03   总分: 15分  得分: _____________

答题人: 游客未登录  开始时间: 25年02月01日 01:21  切换到: 整卷模式

标记此题
1#
 
单选题 ( 1.0 分) (组内1/5) 切至整卷模式 搜藏此题  
第 1 题组 (共 5 题 5 分)
  1. Red-green colour blindness is caused by an X-linked recessive a s 1z,7)7f ; f:nwmp,pqsxtvkdllele. In the pedigree chart below which individuals must be carpf;mvs: zs )kpqt,x1 7fn,7dw riers of the red-green colour blindness allele?


参考答案:    

标记此题
2#
 
单选题 ( 1.0 分) (组内2/5) 切至整卷模式 搜藏此题  
  2. If the parents in the pedigree chart above had a fe ii y)fep+ wtep2;p4/ourth child who was female, what eie2 )f/ yeipt p+w4p;would be the probability that she was colour blind?

参考答案:    

标记此题
3#
 
单选题 ( 1.0 分) (组内3/5) 切至整卷模式 搜藏此题  
  3. In Labrador dogs, black coat is do f/jnlaalvam*,4p 5-8(paietminant over chocolate coat. The genotype of a black male labrador is unknown. How can,nm*aj/p(e taa-ip5l lv8a4f the genotype of this black Labrador be determined?

参考答案:    

标记此题
4#
 
单选题 ( 1.0 分) (组内4/5) 切至整卷模式 搜藏此题  
  4. Which of the following best def.jz9wju39 3gnmosgw+p dh42p0 t9rirines the term, “gene”?

参考答案:    

标记此题
5#
 
单选题 ( 1.0 分) (组内5/5) 切至整卷模式 搜藏此题  
  5. Phenylketonuria (PKU) is an inherited human disease caused by a recessive aut l3fhjmj)3v n.osomal allele in a gene which codes for an enzyme needed to convert phenylalanine to tyrosine. The PK3jjh.l)3v nf mU allele produces a non-functional enzyme.
Which of the following statements are correct?
I. Two parents heterozygous for the condition could have a child with PKU.
II. If the mother of the child is homozygous and not affected by PKU, her children will not be affected.
III. The polypeptide sequence of the enzyme of an affected person is identical to a person without the condition.
IV. Two parents who are not affected with PKU cannot have a child with the disorder.

参考答案:    

标记此题
6#
 
问答题 ( 1.0 分) (组内1/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第1/4题
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
I. Identify which of theea+yp9)s/ruw z c2a8. w1is mw alleles, yellow or green, is dominant.
参考答案:    

标记此题
7#
 
问答题 ( 1.0 分) (组内2/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第2/4题
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
ii. Deduce the genotype of the offsarty+ oap sd *f9yfys.)+o/ c1pring.
参考答案:    

标记此题
8#
 
问答题 ( 1.0 分) (组内3/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第3/4题
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
Iii. Construct a Punnet gri41s l krnq(0r :kybv6bd to show the cross between two offspring plants of the F1 generay6b4k (s rk:l0nqrvb 1tion.
参考答案:    

标记此题
9#
 
问答题 ( 1.0 分) (组内4/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第4/4题
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
Iv. Deduce the phenotypic ratio for the offspridy;p/y g, /ctjk1 np.png of the F1 cross.
参考答案:    

标记此题
10#
 
问答题 ( 1.0 分) (组内1/2) 切至整卷模式 搜藏此题  
第 3 题组 (共 2 题 2 分)
7. Amand has a daughter with Padmavathi. Amand is blood group A, Padmavathiauw,25exp+/fc o smd,x a ehs ,zlx30* is blood group B, and their daughter is blood group O. They are hs +uhso/wf c3 dma0e5xz ,*exx2lpa,, aving a second child, a son.
Deduce the probability that their unborn son will be blood group O. Explain your working.
参考答案:    

标记此题
11#
 
问答题 ( 1.0 分) (组内2/2) 切至整卷模式 搜藏此题  
8. Explain how inheritance and environmental factors can interact in a phenot7wm 4 (4jrqveyype to cause the appearancew(rv 4q4my7e j of human skin colour.
参考答案:    

标记此题
12#
 
问答题 ( 1.0 分) (组内1/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第1/3题
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
a. Deduce genotypes for the three co87 gpzs p -a,zg q4,5x.xjxiywat colour phenotypes in these cattle.
Use the symbols $C^W$ for the white coat allele, and $C^R$for red coat allele.
参考答案:    

标记此题
13#
 
问答题 ( 1.0 分) (组内2/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第2/3题
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
b. Deduce the parental genotypes of the oaw6p5 wl)jzkoc+)t,shuza) lu:c35 cow in the image.
Use P for the allele for polled and p for the allele for horns.
参考答案:    

标记此题
14#
 
问答题 ( 1.0 分) (组内3/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第3/3题
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
c. The roan colour, polle josns74(l xwmll7 m8a7iws77d cow in the image is mated with a white coat, horned bullws7(j8l7 amnix7l7s so4w l 7m.
Construct a Punnett square showing all possible phenotypes of the offspring.
参考答案:    

标记此题
15#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 5 题组 (共 1 题 1 分)
10. The pedigree chart shows ABO/j j cbmk;8*vb blood group alleles and their genotype for nail-patella syndrome, an inheri* /jvcmbkb ;j8ted condition. The individuals 1, 3, and 4 in row III are recombinants. Image by D.B. Pylypiv.

Use the pedigree chart to explain the meaning of gene linkage.
参考答案:    

总分:15分 及格:9分 时间:不限时
未答题: 已答题:0 答错题:
当前第 题,此次习题练习共有 15 道题

浏览记录|手机版试卷|使用帮助|手机版|无忧得胜-网上国际课程 (https://5edu.win)

GMT+8, 2026-1-10 17:38 , Processed in 0.185545 second(s), 73 queries , Redis On.